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Write the molecular formula of the 2nd and 3rd member of the homologous series where the first member is ethyne. - Science

Write the molecular formula of the 2nd and 3rd member of the homologous series where the first member is ethyne.

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Solution

The general formula for the homologous series whose first member is ethyne is CnH2n - 2.

The two consecutive members (2nd and 3rd) of this series are: 

a. CH3CCH (Propyne); where n is 3 

b. CH3CH2CCH(1-Butyne) or CH3CCCH3 (2-Butyne); where n is 4 

The molecular formulae are C3H4 and C4H6, respectively.

  Is there an error in this question or solution?
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