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Write the following cube in expanded form:- `[x-2/3y]^3`
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Solution
`[x-2/3y]^3 = x^3-(2/3y)^3-3(x)(2/3y)(x-2/3y)`
`= x^3-8/27y^3-2xy(x-2/3y)`
`= x^3-8/27y^3-2x^2y+4/3xy^2`
Concept: Algebraic Identities
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