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Write the following cube in expanded form:- `[3/2x+1]^3`
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Solution
`[3/2x+1]^3 = [3/2x]^3 + (1)^3 +3(3/2x)(1)(3/2x+1)`
`= 27/8x^3+1+9/2x(3/2x+1)`
`= 27/8x^3+1+27/4x^2+9/2x`
`= 27/8x^3+27/4x^2+9/2x+1`
Concept: Algebraic Identities
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