Question

Write the first two terms of the sequence whose nth term is t_n = 3n ‒ 4.

Answer 1

t_n = 3n – 4
For n = 1, t₁ = 3 × 1 – 4 = 3 – 4 = –1
For n = 2, t₂ = 3 × 2 – 4 = 6 – 4 = 2
Hence, the first two terms of the sequence are –1 and 2.