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Write the first two terms of the sequence whose nth term is t_{n} = 3n ‒ 4.

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#### Solution

t_{n} = 3n – 4

For n = 1, t_{1} = 3 × 1 – 4 = 3 – 4 = –1

For n = 2, t_{2} = 3 × 2 – 4 = 6 – 4 = 2

Hence, the first two terms of the sequence are –1 and 2.

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