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Write the first three terms of the A.P. whose common difference is ‒3 and first term is 4.

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#### Solution

a = 4, d = –3

Hence,

t_{1} = 4

t_{2} = t_{1} + d = 4 + (–3) = 4 – 3 = 1

t_{3} = t_{2} + d = 1 + (–3) = 1 – 3 = –2

Thus, the first three terms of the A.P. are 4, 1 and –2.

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