Write the equation of each of the following lines:

- The x-axis and the y-axis.
- The line passing through the origin and the point (-3, 5).
- The line passing through the point (-3, 4) and parallel to X-axis.

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#### Solution

1. The required equation of x-axis is y = 0 and y-axis is x = 0.

2. Let P ≡ (0,0) ≡ (x_{1}, y_{1}) and Q ≡ (-3,5) ≡ (x_{2},y_{2})

The required equation is

`(x-x_1)/(x_1-x_2)=("y"-"y"_1)/("y"_1-"y"_2)`

`(x-0)/(0+3)=("y"-0)/(0-5)`

`x/3="y"/-5`

`5x + 3"y"=0`

3. The equation of x-axis line is y = 0

Slope of the line = 0

Required line is parallel to X-axis we know that parallel lines have equal slopes.

Slope of the required line = m= 0 and point (-3, 4) is on the line.

By point slope form of equation,

y - y1 = m(x - x1)

y - 4 = 0(x - (-3))

y = 4 is the required equation.

Concept: General Equation of a Line

Is there an error in this question or solution?

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