# Write the Conjugate of 2 − I ( 1 − 2 I ) 2 . - Mathematics

Write the conjugate of $\frac{2 - i}{\left( 1 - 2i \right)^2}$ .

#### Solution

$\frac{2 - i}{\left( 1 - 2i \right)^2} = \frac{2 - i}{1 + 4 i^2 - 4i}$

$= \frac{2 - i}{1 - 4 - 4i}$

$= \frac{2 - i}{- 3 - 4i}$

$= \frac{- 2 + i}{3 + 4i}$

$= \frac{i - 2}{3 + 4i} \times \frac{3 - 4i}{3 - 4i}$

$= \frac{3i - 4 i^2 - 6 + 8i}{3^2 - 4^2 i^2}$

$= \frac{11i + 4 - 6}{9 + 16}$

$= \frac{- 2}{25} + \frac{11}{25}i$

∴ Conjugate of $\frac{2 - i}{\left( 1 - 2i \right)^2} = \left( \bar{{- \frac{2}{25} + \frac{11}{25}i}} \right) = - \frac{2}{25} - \frac{11}{25}i$

Hence, Conjugate of $\frac{2 - i}{\left( 1 - 2i \right)^2}$  is $- \frac{2}{25} - \frac{11}{25}i$.

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#### APPEARS IN

RD Sharma Class 11 Mathematics Textbook
Chapter 13 Complex Numbers
Q 20 | Page 63