Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads
Sum
Without using trigonometric tables, prove that:
cosec 80° − sec 10° = 0
Advertisement Remove all ads
Solution
LHS = cosec 80° − sec 10°
= `"cosec" (90^circ - 10^circ) - sec 10^circ`
= `sec 10^circ - sec 10^circ`
= 0
= RHS
Concept: Trigonometry
Is there an error in this question or solution?
