Question

Without using trigonometric tables, evaluate :
`sin 16^circ/cos 74^circ`

Answer 1

`sin 16^circ/cos 74^circ`

= `sin (90^circ - 74^circ)/cos 74^circ`

= `cos 74^circ/cos 74^circ` [∵ sin (90-θ) = cos θ ]

= 1