Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads
Sum
Without using trigonometric tables, evaluate :
`("cosec" 42^circ)/sec 48^circ`
Advertisement Remove all ads
Solution
`("cosec" 42^circ)/sec 48^circ`
= `("cosec" (90^circ - 48^circ))/sec 48^circ`
= `sec 48^circ/sec 48^circ` [`because` sec (90-θ) = cosec θ]
= 1
Concept: Trigonometry
Is there an error in this question or solution?
