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Sum
With proper justification, state the negation of the following.
(p → q) ∧ r
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Solution
~[(p → q) ∧ r]
≡ ~ (p → q) ∨ ~ r ....[Negation of conjunction]
≡ (p ∧ ~q) ∨ ~ r ....[Negation of implication]
Is there an error in this question or solution?
