Advertisement Remove all ads

Why Does a Galvanometer Show a Momentary Deflection at the Time of Charging Or Discharging a Capacitor? - Physics

Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads

 

Why does a galvanometer show a momentary deflection at the time of charging or discharging a capacitor? Write the necessary expression to explain this observation.

Advertisement Remove all ads

Solution

 

As the capacitor is connected to the battery, the electrons start moving towards the plate connected to the negative terminal of the battery and electrons leave from the plate connected to the positive terminal of the battery. This happens until the potential of the capacitor becomes equal to that of the battery. As this happens very quickly, the charging current produces a deflection. The reverse process is repeated for discharging that is the charge is lost. As the galvanometer can be considered as a resistance, the circuit behaves like a R-C circuit having time constant equal to RC. Hence the expression governing this phenomenon is

`q=q_0(1-e^(-t/(RC)))`

Concept: Moving Coil Galvanometer
  Is there an error in this question or solution?

Video TutorialsVIEW ALL [2]

Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×