Sum
When `x^3 + 2x ^2– kx + 4 `is divided by x – 2, the remainder is k. Find the value of constant k.
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Solution
Left f(x)=`x^3+2x^2-kx+4`
x-2=0⇒x=2
on dividing f (x) by x-2,, it leaves a remainder K.
∴ f(2)=k
`(2)^3+2(2)^2-k(2)+4=k`
`8+8-2k+4=k`
`20=3k`
`k=20/3=6(2)/3`
Concept: Remainder Theorem
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