Answer 1

\[\text{ Possible outcomes when two dice are rolled }: \]
\[S = \left\{ \left( 1, 1 \right), \left( 1, 2 \right), \left( 1, 3 \right), \left( 1, 4 \right), \cdots, \left( 6, 5 \right), \left( 6, 6 \right) \right\}\]
\[\text{ Therefore, the number of possible outcomes in the sample space is 36 }. \]

\[\text{ The number of favourable outcomes is 6 }. \]
\[ \therefore P\left( B \right) = \frac{6}{36} = \frac{1}{6}\]