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MCQ
Fill in the Blanks
When Cl2 reacts with hot and conc. NaOH, the oxidation number of chlorine changes from ____________.
Options
zero to +1 and zero to +5
0 to −1 and 0 to +5
zero to −1 and zero to +3
0 to +1 and 0 to −3
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Solution
When Cl2 reacts with hot and conc. NaOH, the oxidation number of chlorine changes from 0 to −1 and 0 to +5.
Explanation:
Cl2 has oxidation number 0, in Cl (−1) and in ClO3 (+5).
\[\ce{3Cl2 + 6NaOH ({hot and conc.}) -> 5NaCl + NaClO3 + 3H2O}\]
Concept: P - Block Group 17 Elements - Chlorine
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