# When an Inductor is Connected to a 200 V Dc Voltage, a Current at 1a Flows Through It. When the Same Inductor is Connected to a 200 V, 50 Hz Ac Source, Only 0.5 a Current Flows. Explain, Why? - Physics

When an inductor is connected to a 200 V dc voltage, a current at 1A flows through it. When the same inductor is connected to a 200 V, 50 Hz ac source, only 0.5 A current flows. Explain, why? Also, calculate the self-inductance of the inductor.

#### Solution

When the inductor is connected across the 200 V DC circuit 1 A current flows because in this case the inductor simply acts as a resistor and there is no inductive reactance. Whereas, when we connect the same inductor across 200 V AC, due to inductive reactance the overall impedance is changed and hence the value of current also changes.

When the inductor is connected across 200 V DC

The resistance of the coil

R = 200/1 = 200 Ω

Let the self-inductance of the inductor be L,
When the inductor is connected across 200 V A.C.

Net impedance, Z = sqrt((2pifL)^2 + R^2) = 200/0.5 = 400 Omega

⇒ (2pi xx 50 xx L)^2 + 200^2 = 400^2

⇒ (100piL)^2 = 160000 - 40000

⇒ 10000pi^2L^2 = 120000

⇒ L^2 = 12/pi^2

therefore L = sqrt(12)/pi H

Concept: Inductance - Self Inductance
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