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# When a conducting loop of resistance 10 Ω and area 10 cm2 is removed from an external magnetic field acting normally, the variation of induced current-I in the loop with time t is as - Physics

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Short Note

Answer the following question.
When a conducting loop of resistance 10 Ω and area 10 cm2 is removed from an external magnetic field acting normally, the variation of induced current-I in the loop with time t is as shown in the figure.
Find the
(a) total charge passed through the loop.
(b) change in magnetic flux through the loop
(c) magnitude of the field applied Advertisement Remove all ads

#### Solution

I = ("dq")/("dt") ⇒ "dq = "I"d"t"

Hence area under the I-t curve gives charge flown.
Area of the I-t curve (as given in the question) = 1/2 xx 2 xx 1/2 = 0.5
Total charge passed through the loop = 0.5 C

Now we know
Δ"Q" = (Δvarphi)/"R"
Δvarphi = Δ"Q" xx "R" = 1/2 xx 10Omega = 5  "Wb"

Charge in magnetic flux through the loop= 5 Wb
Δvarphi = "B"  (Δ"A")
5 = "B"  (0.001)
"B" = 5000 "T"
The magnitude of the field applied = 5000 T

Concept: Magnetic Flux
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