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When 2.56 g of sulphur was dissolved in 100 g of CS2, the freezing point lowered by 0.383 K. Calculate the formula of sulphur (Sx). - Chemistry

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When 2.56 g of sulphur was dissolved in 100 g of CS2, the freezing point lowered by 0.383 K. Calculate the formula of sulphur (Sx).

(Kf for CS2 = 3.83 K kg mol−1, Atomic mass of sulphur = 32 g mol−1]

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Solution

Given:

Kf = 3.83 K kg mol1

Mass of solute = 2.56 g

Mass of solvent = 100 g

Therefore,

`"Molality of the solution, "m =2.56/32xx1000/100=0.8m`

The depression in freezing point of a solution is given as

∆Tf = iKfm

0.383= i×3.83×0.8

i = 1/8

Hence, 8 sulphur atoms are undergoing association, as shown below:

8 S â‡Œ S8

Concept: Colligative Properties and Determination of Molar Mass - Depression of Freezing Point
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