What will be the minimum pressure required to compress 500 dm3 of air at 1 bar to 200 dm3 at 30°C?
Initial pressure, p1 = 1 bar
Initial volume, V1 = 500 dm3
Final volume, V2 = 200 dm3
Since the temperature remains constant, the final pressure (p2) can be calculated using Boyle’s law.
According to Boyle’s law,
`p_1V_1 = p_2V_2`
`=>p_2 = (p_1V_1)/V_2`
`= (1xx500)/200 "bar"`
`= 2.5 "bar"`
Therefore, the minimum pressure required is 2.5 bar.
P1 = 1 bar,P2 = ? V1= 500 dm3 ,V2=200 dm3
As temperature remains constant at 30°C,
1 bar x 500 dm3 = P2 x 200 dm3 or P2=500/200 bar=2.5 bar
Video Tutorials For All Subjects
- Intermolecular Forces - Introduction