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What Weight of Each Element is Present in 1.5 Moles of Sodium Sulphite, Na2so3 ? (Atomic Masses : Na = 23 U ; S = 32 U ; O = 16 U) - Science

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Short Note

What weight of each element is present in 1.5 moles of sodium sulphite, Na2SO3 ?

(Atomic masses : Na = 23 u ; S = 32 u ; O = 16 u)

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Solution

1.5 moles of sodium sulphite

Molar mass of sodium sulphite = (2 × 23) + (1 × 32) + (3 × 16) = 126g

Therefore, 1 mole of sodium sulphite weighs 126g.
Now, 1 mole of sodium sulphite contains 2 moles of sodium.

So, mass of sodium in 1 mole of sodium sulphite = 2 × 23 = 46g

Therefore, mass of sodium in 1.5 moles of sodium sulphite is = 1.5 × 46 = 69g

1 mole of sodium sulphite contains 1 mole of sulphur.

So, mass of sulphur in 1 mole of sodium sulphite = 1 × 32 = 32g

Therefore, mass of sulphur in 1.5 moles of sodium sulphite is = 1.5 × 32 = 48g

1 mole of sodium sulphite contains 3 moles of oxygen.

So, mass of oxygen in 1 mole of sodium sulphite = 3 × 16 = 48g

Therefore, mass of oxygen in 1.5 moles of sodium sulphite is = 1.5 × 48 = 72g

Hence, the mass of sodium, sulphur and oxygen in sodium sulphite is 69g, 48g and 72g, respectively.

Concept: Mole Concept
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APPEARS IN

Lakhmir Singh Class 9 Chemistry - Science Part 2
Chapter 3 Atoms and Molecules
Long Answers | Q 31.2 | Page 173

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