Share

What Volume of Propane is Consumed on Using 1000 Cm3 of Air, Considering Only 20% of Air Contains Oxygen? - ICSE Class 10 - Chemistry

ConceptGay Lussac’s Law of Combining Volumes

Question

Propane burns in air according to the following equation:

C3H8 + 5O2 → 3CO2 + 4H2O

What volume of propane is consumed on using 1000 cm3 of air, considering only 20% of air contains oxygen?

Solution

Given:

C3H8 + 5O2 → 3CO2 + 4H2O

Volume of air = 1000 cm3

Percentage of oxygen in air = 20%

From the given information

C3H8  +  5O2  → 3CO2  +  4H2O
1vol        5vols     3vols       4vols

According to Gay-Lussac’s law,
1 vol. of propane consumes 5 vol. of oxygen

Volume of oxygen = 1000 cm3 × 20% = 200 cm3

Therefore,
Volume of propane burnt for every 200 cm3 of oxygen

= 1/5 xx  200 = 40 cm^3

40 cm3 of propane is burnt.

Is there an error in this question or solution?

APPEARS IN

Solution What Volume of Propane is Consumed on Using 1000 Cm3 of Air, Considering Only 20% of Air Contains Oxygen? Concept: Gay Lussac’s Law of Combining Volumes.
S