Share

# What Volume of Propane is Consumed on Using 1000 Cm3 of Air, Considering Only 20% of Air Contains Oxygen? - ICSE Class 10 - Chemistry

ConceptGay Lussac’s Law of Combining Volumes

#### Question

Propane burns in air according to the following equation:

C3H8 + 5O2 → 3CO2 + 4H2O

What volume of propane is consumed on using 1000 cm3 of air, considering only 20% of air contains oxygen?

#### Solution

Given:

C3H8 + 5O2 → 3CO2 + 4H2O

Volume of air = 1000 cm3

Percentage of oxygen in air = 20%

From the given information

C3H8  +  5O2  → 3CO2  +  4H2O
1vol        5vols     3vols       4vols

According to Gay-Lussac’s law,
1 vol. of propane consumes 5 vol. of oxygen

Volume of oxygen = 1000 cm3 × 20% = 200 cm3

Therefore,
Volume of propane burnt for every 200 cm3 of oxygen

= 1/5 xx  200 = 40 cm^3

40 cm3 of propane is burnt.

Is there an error in this question or solution?

#### APPEARS IN

Solution What Volume of Propane is Consumed on Using 1000 Cm3 of Air, Considering Only 20% of Air Contains Oxygen? Concept: Gay Lussac’s Law of Combining Volumes.
S