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What Volume of Nitrogen at Stp, Will Be Evolved When 63g of Ammonium Dichromate is Decomposed? - Chemistry

Sum

(NH4)2Cr2O7 → N2 + Cr2O3 +4H2O.
What volume of nitrogen at STP, will be evolved when 63g of ammonium dichromate is decomposed?
(H= 1, N = 14, 0 = 16, Cr = 52)

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Solution

Molecular mass of ammonium dichromate = 252
Now, 252g of ammonium dichromate evolves= 22.4 L of nitrogen at STP
63g of ammonium dichromate will evolve= 22.4 x 63 /252 = 5.6L
So, 63g of ammonium dichromate will evolve 5.6L of oxygen.

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APPEARS IN

Frank ICSE Class 10 Chemistry Part 2
Chapter 5 Mole Concept And Stoichiometry
Exercise | Q 8 | Page 117
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