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What value of y would make AOB a line in below fig, if ∠AOC = 4y and ∠BOC = (6y +

30)

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#### Solution

Since `∠`*AOC*, `∠`*BOC *are linear pair

*⇒ *`∠`*AOC *+ `∠`*BOC *= 180°

*⇒ *6 *y *+ 30 + 4 *y *= 180°

*⇒* 10 *y *+ 30 = 180°

*⇒ *10 *y *= 180° - 30°

*⇒* 10 *y *= 150°

*⇒ y *= `(150°)/10`

*⇒ y *= 15°

Concept: Pairs of Angles

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