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What is the Value of Sin 2 θ + 1 1 + Tan 2 θ - Mathematics

Answer in Brief

What is the value of \[\sin^2 \theta + \frac{1}{1 + \tan^2 \theta}\]

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Solution

We have, 

`sin^2 θ+1/(1+tan^2θ)= sin^2θ+1/(sqc^2θ)` 

=` sin^2θ+(1/secθ)^2`  

=` sin^2 θ+cos^2θ` 

=` 1`

 

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APPEARS IN

RD Sharma Class 10 Maths
Chapter 11 Trigonometric Identities
Q 4 | Page 55
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