# What is the Total Capacitance of the Combination Each of Capacitance 9 Pf Are Connected in Series? - Physics

Numerical

Three capacitors each of capacitance 9 pF are connected in series.

(a) What is the total capacitance of the combination?

(b) What is the potential difference across each capacitor if the combination is connected to a 120 V supply?

#### Solution

(a) Capacitance of each of the three capacitors, C = 9 pF

Equivalent capacitance (C') of the combination of the capacitors is given by the relation,

1/"C'" = 1/"C" + 1/"C" + 1/"C"

=> 1/"C'" = 1/9 + 1/9 + 1/9 = 1/3

=> C' = 3 pF

Therefore, the total capacitance of the combination is 3 pF.

(b) Supply voltage, V = 120 V

Potential difference (V') across each capacitor is equal to one-third of the supply voltage.

∴ "V'" = "V"/3 = 120/3 = 40 V

Therefore, the potential difference across each capacitor is 40 V.

Concept: Combination of Capacitors
Is there an error in this question or solution?

#### APPEARS IN

NCERT Physics Part 1 and 2 Class 12
Chapter 2 Electrostatic Potential and Capacitance
Exercise | Q 2.6 | Page 86
NCERT Class 12 Physics Textbook
Chapter 2 Electrostatic Potential and Capacitance
Exercise | Q 6 | Page 87

Share