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What Should Be Taken Away from 3x2 - 4y2 + 5xy + 20 to Obtain - X2 - Y2 + 6xy + 20? - Mathematics

What should be taken away from 3x2 - 4y2 + 5xy + 20 to obtain - x2 - y2 + 6xy + 20?

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Solution

Let p be the required term.

(3x2 - 4y2 + 5xy + 20) - p = - x2 - y2 + 6xy + 20

p = (3x2 - 4y2 + 5xy + 20) - (- x2 - y2 + 6xy + 20)

= 3x2 - 4y2 + 5xy + 20 + x2 + y2 - 6xy - 20

= 3x2 + x2 - 4y2 + y2 + 5xy - 6xy + 20 - 20

= 4x2 - 3y2 - xy

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APPEARS IN

NCERT Class 7 Maths
Chapter 12 Algebraic Expressions
Exercise 12.2 | Q 5 | Page 240
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