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What is the ratio of volumes of H2 and O2 liberated during electrolysis of acidified water? - Chemistry

What is the ratio of volumes of H2 and O2 liberated during electrolysis of acidified water?

(A) 1 : 2

(B) 2 : 1

(C) 1 : 8

(D) 8 : 1

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Solution

2 : 1

The reaction occuring during electrolysis of acidified water is

Thus the ratio of number of moles (n) of H2 and O2 liberated is 2 : 1

But volume V ∝ n (∵ PV = nRT)

∴ The ratio of volumes of H2 and O2 liberated is 2 : 1

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