# What is the Ph of 0.001 M Aniline Solution? the Ionization Constant of Aniline Can Be Taken from Table 7.7. Calculate the Degree of Ionization of Aniline in the Solution. Also Calculate the Ionization Constant of the Conjugate Acid of Aniline - Chemistry

What is the pH of 0.001 M aniline solution? The ionization constant of aniline can be taken from Table 7.7. Calculate the degree of ionization of aniline in the solution. Also calculate the ionization constant of the conjugate acid of aniline

#### Solution

Kb = 4.27 × 10–10

c = 0.001M

pH =?

α =?

k_b = calpha^2

4.27 xx 10^(-10)= 0.0014 xx alpha^2

4270 xx 10^(-10) = alpha^2

65.34 xx 10^(-5) = alpha = 65.34 xx 10^(-4)

Then [anoin] = calpha = .001 xx 65.34 xx 10^(-5)

= .065 xx 10^(-5)

pOH = -log (.065 xx 10^(-5))

= 6.187

pH = 7.813

Now,

K_a xx K_b = K_w

:. 4.27 xxx 10^(-10) xx K_a = K_w

K_a = 10^(-14)/(4.27xx 10^(-10))

= 2.34 xx 10^(-5)

Thus, the ionization constant of the conjugate acid of aniline is 2.34 × 10–5.

Concept: Ionization of Acids and Bases - Ionization of Weak Bases
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#### APPEARS IN

NCERT Class 11 Chemistry Textbook
Chapter 7 Equilibrium
Q 52 | Page 229