Sum
What least number be subtracted from each of the numbers 7, 17 and 47 so that the remainders are in continued proportion?
Advertisement Remove all ads
Solution
Let the number subtracted be x
∴ (7 - x) : (17 - x) :: (17 - x)(47 - x)
`(7 - x)/(47 - x) = (17 - x)^2`
`329 - 47x - 7x + x^2 = 289 - 34x = x^2`
329 - 289 = -34x + 54x
20x = 40
x = 2
Thus the required number which should be subtracted is 2
Concept: Concept of Proportion
Is there an error in this question or solution?
Advertisement Remove all ads
APPEARS IN
Advertisement Remove all ads
Advertisement Remove all ads
