What Least Number Must Be Subtracted from Each of the Numbers 7, 17 and 47 So that the Remainders Are in Continued Proportion? - Mathematics
What least number be subtracted from each of the numbers 7, 17 and 47 so that the remainders are in continued proportion?
Let the number subtracted be x
∴ (7 - x) : (17 - x) :: (17 - x)(47 - x)
`(7 - x)/(47 - x) = (17 - x)^2`
`329 - 47x - 7x + x^2 = 289 - 34x = x^2`
329 - 289 = -34x + 54x
20x = 40
x = 2
Thus the required number which should be subtracted is 2
Is there an error in this question or solution?
why create a profile on Shaalaa.com?
1. Inform you about time table of exam.
2. Inform you about new question papers.
3. New video tutorials information.