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What least number must be added to 1056 to get a number exactly divisible by 23? - Mathematics

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What least number must be added to 1056 to get a number exactly divisible by 23?

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Solution

First, we will divide 1056 by 23.

Required number = 23 − 21 = 2
So, 2 must be added to 1056 to make it exactly divisible by 23.
i.e., 1056 + 2 = 1058
Now, we have:

∴ 1058 is exactly divisible by 23.

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APPEARS IN

RS Aggarwal Class 6 Mathematics
Chapter 3 Whole Numbers
Exercise 3E | Q 9 | Page 56
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