What is the shortest wavelength present in the Paschen series of spectral lines? - Physics

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Numerical

What is the shortest wavelength present in the Paschen series of spectral lines?

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Solution

Rydberg’s formula is given as:

` "hc"/lambda = 21.76 xx 10^(-19) [1/"n"_1^2 - 1/"n"_2^2]`

Where,

h = Planck’s constant = 6.6 × 10−34 Js

c = Speed of light = 3 × 10m/s

(n1 and n2 are integers)

The shortest wavelength present in the Paschen series of the spectral lines is given for values n1 = 3 and n2 = ∞.

`"hc"/lambda = 21.76 xx 10^(-19) [1/(3)^2 - 1/(∞)^2]`

`lambda = (6.6 xx 10^(-34) xx 3 xx 10^8 xx 9)/(21.76 xx 10^(-19)`

= 8.189 × 10−7 m

= 818.9 nm

Concept: Atomic Spectra
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Chapter 12: Atoms - Exercise [Page 436]

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NCERT Physics Class 12
Chapter 12 Atoms
Exercise | Q 12.3 | Page 436
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Chapter 12 Atoms
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