# What is the force of repulsion if each sphere is charged double the above amount, and the distance between them is halved? - Physics

Numerical

What is the force of repulsion if each sphere is charged double the above amount, and the distance between them is halved?

#### Solution

After doubling the charge, charge on sphere A, qA = Charge on sphere B, qB = 2 × 6.5 × 10−7 C = 1.3 × 10−6 C

The distance between the spheres is halved.

∴ "r" = 0.5/2 = 0.25 m

Force of repulsion between the two spheres,

"F" = ("q"_"A""q"_"B")/(4piin_0r^2)

= (9 xx 10^9 xx 1.3 xx 10^-6 xx 1.3 xx 10^-6)/((0.25)^2)

= 16 × 1.52 × 10−2

= 0.243 N

Therefore, the force between the two spheres is 0.243 N.

Concept: Charging by Induction
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Chapter 1: Electric Charges and Fields - Exercise [Page 47]

#### APPEARS IN

NCERT Physics Part 1 and 2 Class 12
Chapter 1 Electric Charges and Fields
Exercise | Q 1.12 (b) | Page 47
NCERT Class 12 Physics Textbook
Chapter 1 Electric Charge and Fields
Exercise | Q 12.2 | Page 47
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