Advertisement Remove all ads

Advertisement Remove all ads

Advertisement Remove all ads

Short Note

What is meant by escape speed in the case of the Earth?

Advertisement Remove all ads

#### Solution

The escape speed is independent of the direction in which the object is thrown. Irrespective of whether the object is thrown vertically up, radially outwards or tangentially it requires the same initial speed to escape Earth’s gravity force.

This can be written as v_{e} = `sqrt(2"g""R"_"E")`

Concept: Escape Speed and Orbital Speed

Is there an error in this question or solution?