# What is the Force of Repulsion If Each Sphere is Charged Double the Above Amount, and the Distance Between Them is Halved? - Physics

What is the force of repulsion if each sphere is charged double the above amount, and the distance between them is halved?

#### Solution

After doubling the charge, charge on sphere A, qA = Charge on sphere B, qB = 2 × 6.5 × 10−7 C = 1.3 × 10−6 C

The distance between the spheres is halved.

therefor r=0.5/2=0.25 m

Force of repulsion between the two spheres,

F=(q_Aq_B)/(4piin_0r^2)

=(9xx10^9xx1.3xx10^-6xx1.3xx10^-6)/((0.25)^2)

= 16 × 1.52 × 10−2

= 0.243 N

Therefore, the force between the two spheres is 0.243 N.

Concept: Charging by Induction
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#### APPEARS IN

NCERT Class 12 Physics Textbook
Chapter 1 Electric Charge and Fields
Q 12.2 | Page 47