Advertisement Remove all ads

What is the Balancing Length for Its Terminal Potential Difference When Shunted with Resistance R - Physics

Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads
MCQ

In potentiometer experiment, if l1 is the balancing length for e.m.f. of cell of internal resistance r and l2 is the balancing length for its terminal potential difference when shunted with resistance R then :

Options

  • `l_1=l_2((R+r)/R)`

  • `l_1=l_2((R)/(R+r))`

  • `l_1=l_2((R)/(R-r))`

  • `l_1=l_2((R-r)/R)`

Advertisement Remove all ads

Solution

`l_1=l_2((R+r)/R)`

The internal resistance of a cell is given as

`r= ((l_1-l_2)/l_2)R`

→`r/R=(l_1-l_2)/l_2`

∴ `rl_2=Rl_1-Rl_2`

∴`l_2(R+r)=Rl_1`

∴`l_1=l_2(R+r)/R`

Concept: Metre Bridge
  Is there an error in this question or solution?

APPEARS IN

Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×