Question
What are the oxidation numbers of the underlined elements in each of the following and how do you rationalise your results?
CH3CH2OH
Solution 1
By conventional method O.N of C in CH_3CH_2OH = 
or 2x + 6(+1) + 1(-2) = 0 or x = -2
Solution 2
CH3CH2OH
2(x) + 6(+1) + 1(-2) = 0 or 2x + 4 = 0
or x = -2
Hence, the O.N. of C is –2.
Is there an error in this question or solution?
Solution What Are the Oxidation Numbers of the Underlined Elements in Each of the Following and How Do You Rationalise Your Results?Ch3ch2oh Concept: Oxidation Number - Introduction.
