What Are the Oxidation Numbers of the Underlined Elements in Each of the Following and How Do You Rationalise Your Results?Ch3ch2oh - Chemistry
What are the oxidation numbers of the underlined elements in each of the following and how do you rationalise your results?
2(x) + 6(+1) + 1(-2) = 0 or 2x + 4 = 0
or x = -2
Hence, the O.N. of C is –2.
By conventional method O.N of C in CH_3CH_2OH =
or 2x + 6(+1) + 1(-2) = 0 or x = -2
Concept: Oxidation Number - Introduction
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