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What Are the Oxidation Numbers of the Underlined Elements in Each of the Following and How Do You Rationalise Your Results?Ch3ch2oh - Chemistry

What are the oxidation numbers of the underlined elements in each of the following and how do you rationalise your results?

CH3CH2OH

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Solution 1

CH3CH2OH

2(x) + 6(+1) + 1(-2) = 0 or 2x + 4 = 0

or x = -2

Hence, the O.N. of C is –2.

Solution 2

By conventional method O.N of C  in CH_3CH_2OH = 

or 2x + 6(+1) + 1(-2) = 0 or x = -2

Concept: Oxidation Number - Introduction
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APPEARS IN

NCERT Class 11 Chemistry Textbook
Chapter 8 Redox Reactions
Q 2.4 | Page 272
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