# What is (A) Highest, and (B)ω Lowest, Resistance Which Can Be Obtained by Combining Four Resistors Having the Following Resistances? 4 ω, 8 ω, 12 ω, 24 ω - Science

What is (a) highest, and (b)Ω lowest, resistance which can be obtained by combining four resistors having the following resistances?

4 Ω, 8 Ω, 12 Ω, 24 Ω

#### Solution

(a) To get the highest resistance, all the resistors must be connected in series.
Resistance in a series arrangement is given by R = R1R2 + R3 + R

R=4Ω+8Ω+12Ω+24Ω

R=48Ω

Therefore, the highest resistance is 48 Ω.
(b) To get the lowest resistance, all the resistors must be connected in parallel.
Resistance in a parallel arrangement is given by:

1/R=1/R_1+1/R_2+1/R_3+1/R_4

HereR_1=4Ω

R_2=8 Ω

R_3=12 Ω

R_4=24Ω

1/R=1/4+1/8+1/12+1/24

1/R=(6+3+2+1)/24

1/R=12/24

R=2Ω

Therefore, the lowest resistance of the arrangement is 2 Ω.

Concept: System of Resistors - Resistors in Series
Is there an error in this question or solution?