#### Question

Light of wavelength 3000Å falls on a metal surface having work function 2.3 eV. Calculate the maximum velocity of ejected electrons

(Planck's constant h = 6.63 x 10^{-34} J.s., Velocity of light c = 3 x 10^{8} m/s, mass of an electron = 9.1 x 10^{-31} kg)

#### Solution

Given: λ = 3000 Å = 3 x 10^{–7} m, m_{e} = 9.1 10^{–31} kg,

Φo = 2.3 eV, h = 6.63 10^{–34} Js, c = 3 10^{8} m/s

To find: Maximum velocity (v_{max})

Formula: (K.E)_{max }= `(hc)/λ - Φ_o`

Calculation: From formula,

= 8.052 x 10^{5} m/s

The maximum velocity of electron is 8.052 x 10^{5} m/s

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#### APPEARS IN

Solution Light of Wavelength 3000å Falls on a Metal Surface Having Work Function 2.3 Ev. Calculate the Maximum Velocity of Ejected Electrons Concept: Wave Theory of Light.