#### Question

Calculate the wavelength, frequency and wave number of a light wave whose period is 2.0 × 10^{–10}s.

#### Solution

Frequency (*ν*) of light = `1/"Period"`

`= 1/(2.0 xx 10^(-10)s) = 5.0 xx 10^9 s^(-1)`

Wavelength (*λ*) of light = `c/v`

Where,

c = velocity of light in vacuum = 3×10^{8} m/s

Substituting the value in the given expression of *λ**:*

`lambda = (3xx10^8)/(5.0xx10^9) = 6.0 xx 10^(-2)m`

Wave number (`barv`) of light =` 1/lambda = 1/(6.0xx10^(-2)) = 1.66xx 10^(-1) = 16.66 m`

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Solution Calculate the Wavelength, Frequency and Wave Number of a Light Wave Whose Period is 2.0 × 10 Concept: Wave Nature of Electromagnetic Radiation.