Discuss the principle and method of softening of hard water by synthetic ion-exchange resins.
Cation exchange resins have large organic molecule with S03H group which are insoluble in water. Ion exchange resin (RS03H) is changed to RNa on treatment with NaCl. The resin exchange Na+ ions with Ca2+ and Mg2+ ions present in hard water and make it soft.
2RNa(s) + M2+(aq) ——> R2M(s) + 2Na+(aq)
where, M = Mg, Ca.
The resins can be regenerated by adding aqueous NaCl solution.
The process of treating permanent hardness of water using synthetic resins is based on the exchange of cations (e.g., Na+, Ca2+, Mg2+ etc) and anions (e.g., Cl–, SO42–, HCO3– etc) present in water by H+ and OH– ions respectively.
Synthetic resins are of two types:
1) Cation exchange resins
2) Anion exchange resins
Cation exchange resins are large organic molecules that contain the –SO3H group. The resin is firstly changed to RNa (from RSO3H) by treating it with NaCl. This resin then exchanges Na+ ions with Ca2+ and Mg2+ ions, thereby making the water soft.
`2RNa + M_((aq))^(2+) -> R_2M_(s) + 2Na_((aq))^+`
There are cation exchange resins in H+ form. The resins exchange H+ ions for Na+, Ca2+, and Mg2+ ions.
`2RH + M_((aq))^(2+) ⇌ MR_(2(s)) + 2H_((aq))^+`
Anion exchange resins exchange OH– ions for anions like Cl–, `HCO_3^-`, and SO42–present in water.
During the complete process, water first passes through the cation exchange process. The water obtained after this process is free from mineral cations and is acidic in nature.
This acidic water is then passed through the anion exchange process where OH– ions neutralize the H+ ions and de-ionize the water obtained.