# Water in a canal, 6 m wide and 1.5 m deep, is flowing at a speed of 4 km/hr. How much area will it irrigate in 10 minutes if 8 cm of standing water is needed for irrigation? - Mathematics

Sum

Water in a canal, 6 m wide and 1.5 m deep, is flowing at a speed of 4 km/hr. How much area will it irrigate in 10 minutes if 8 cm of standing water is needed for irrigation?

#### Solution

We have,

Width of the canal, b = 6 m

Depth of the canal, h = 1.5 m,

Height of the standing water needed for irrigation, H=8 cm = 0.08 m,

speed of the flowing water, l=4 km / h = 4000/60 = 200/3 "m"// "min"

Now,

Volume of water flowing out from canal in 1 min =lbh

=200/3xx6xx1.5

=600 m2

⇒ Volume of water flowing out from canal in 10 min = 600 × 10 = 6000 m

"so, the area of irrigation" = "Volume of water flowing out from canal in 10 min"/"Height of the standing water needed for irrigation"

= 6000/0.08

= 75000 m2

= 7.5 hectare    (As, 1 hectare = 10000 m2)

Hence, it will irrigate 7.5 hectare of area in 10 minutes.

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#### APPEARS IN

RS Aggarwal Secondary School Class 10 Maths
Chapter 19 Volume and Surface Area of Solids
Exercise 19B | Q 26 | Page 899