Question
Water in a canal 1.5m wide and 6m deep is flowering with a speed of 10km/ hr. how much area will it irrigate in 30 minutes if 8cm of standing water is desired?
Solution
Given that water is flowering with a speed = 10km / hr.
In 30 minutes length of flowering standing water = 10 x `30/60km`
= 5km = 5000m.
Volume of flowering water in 30 minutes
V = 5000 x width x xdepth m3
Given width of canal = 1.5m
Depth of canal = 6m
V = 5000 x 1.5 x 6m3
V = 45000m3
Irrigating area in 30 minutes if 8cm of standing water is desired = `45000/0.08`
=`45000/0.08` = 562500m2
∴ Irrigated area in 30minutes = 562500m2
Is there an error in this question or solution?
Solution Water in a Canal 1.5m Wide and 6m Deep is Flowering with a Speed of 10km/ Hr. How Much Area Will It Irrigate in 30 Minutes If 8cm of Standing Water is Desired? Concept: Volume of a Combination of Solids.
