Water in a canal 1.5m wide and 6m deep is flowering with a speed of 10km/ hr. how much area will it irrigate in 30 minutes if 8cm of standing water is desired?

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#### Solution

Given that water is flowering with a speed = 10km / hr.

In 30 minutes length of flowering standing water = 10 x `30/60km`

= 5km = 5000m.

Volume of flowering water in 30 minutes

V = 5000 x width x xdepth m^{3}

Given width of canal = 1.5m

Depth of canal = 6m

V = 5000 x 1.5 x 6m^{3}

V = 45000m^{3}

Irrigating area in 30 minutes if 8cm of standing water is desired = `45000/0.08`

=`45000/0.08` = 562500m^{2}

∴ Irrigated area in 30minutes = 562500m^{2}

Concept: Volume of a Combination of Solids

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