#### Question

A measuring jar of internal diameter 10 cm is partially filled with water. Four equal spherical balls of diameter 2 cm each are dropped in it and they sink down in water completely. What will be the change in the level of water in the jar?

#### Solution

Given that,

Diameter of jar = 10cm

Radius of jar = 5cm

Let the level of water raised by ‘h’

Diameter of spherical ball = 2cm

Radius of the ball =1cm

Volume of jar = 4(Volume of spherical)

⇒ `πr_1^2h=4(4/3πr_2^3)`

⇒`r_1^2h=4xx4/3r_2^3`

⇒`r_1^2h=4xx4/3xx1xx1xx1`

⇒`h=(4xx4xx1)/(3xx5xx5)`

⇒`h=16/75cm.`

∴ Height of water in jar`16/75`cm.

Is there an error in this question or solution?

Solution for question: A Measuring Jar of Internal Diameter 10 Cm is Partially Filled with Water. Four Equal Spherical Balls of Diameter 2 Cm Each Are Dropped in It and They Sink Down in Water Completely, Change Level Jar? concept: Volume of a Sphere. For the course CBSE