#### Question

A cylindrical tub of radius 12 cm contains water to a depth of 20 cm. A spherical form ball is dropped into the tub and thus the level of water is raised by 6.75 cm. What is the radius of the ball?

#### Solution

A cylindrical tub of radius = 12cm

Depth = 20cm.

Let r cm be the radius of the ball

Then, volume of ball = volume of water raised

=`4/3πr^3 = π r^2h`

=`4/3πr^3 = π xx(12)^2 xx6.75`

⇒ `r^3=(144xx6.75xx3)/4`

⇒ `r^3=729`

⇒ r = 9cm

Thus, radius of the ball = 9cm.

Is there an error in this question or solution?

Solution for question: A Cylindrical Tub of Radius 12 Cm Contains Water to a Depth of 20 Cm. a Spherical Form Ball is Dropped into the Tub and Thus the Level of Water is Raised by 6.75 Cm. What is the Radius of the Ball? concept: Volume of a Sphere. For the course CBSE