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# A Wall of Length 10 M Was to Be Built Across an Open Ground. the Height of the Wall is 4 M and Thickness of the Wall is 24 Cm. - CBSE Class 9 - Mathematics

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ConceptVolume of a Cuboid

#### Question

A wall of length 10 m was to be built across an open ground. The height of the wall is 4 m and thickness of the wall is 24 cm. If this wall is to be built up with bricks whose dimensions are 24 cm × 12 cm × 8 cm, How many bricks would be required?

#### Solution

Given that
The wall with all its bricks makes up the space occupied by it we need to find the volume of the wall, which is nothing but cuboid.
Here, length= 10m = 1000cm
Thickness=24cm
∴The volume of the wall
= length × breadth × height
1000xx24xx400cm^3

Now, each brick is a cuboid with length = 24cm,
Breadth= 12cm and height= 8cm.
So, volume of each brick = length x breadth x height
=24xx12xx8cm^3

So, number of bricks required="Volume of the wall"/"Volume of each brick"

=(1000xx24xx400)/(24xx12xx8)
=4166.6
"So, the wall requires 167 bricks".

Is there an error in this question or solution?

#### APPEARS IN

RD Sharma Solution for Mathematics for Class 9 by R D Sharma (2018-19 Session) (2018 to Current)
Chapter 18: Surface Areas and Volume of a Cuboid and Cube
Ex.18.20 | Q: 19 | Page no. 31
Solution A Wall of Length 10 M Was to Be Built Across an Open Ground. the Height of the Wall is 4 M and Thickness of the Wall is 24 Cm. Concept: Volume of a Cuboid.
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