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Solution for Water in a Canal 1.5m Wide and 6m Deep is Flowering with a Speed of 10km/ Hr. How Much Area Will It Irrigate in 30 Minutes If 8cm of Standing Water is Desired? - CBSE Class 10 - Mathematics

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Question

Water in a canal 1.5m wide and 6m deep is flowering with a speed of 10km/ hr. how much area will it irrigate in 30 minutes if 8cm of standing water is desired?

Solution

Given that water is flowering with a speed = 10km / hr.

In 30 minutes length of flowering standing water = 10 x `30/60km`

= 5km = 5000m.

Volume of flowering water in 30 minutes

V = 5000 x width x xdepth m3

Given width of canal = 1.5m

Depth of canal = 6m

V = 5000 x 1.5 x 6m3

V = 45000m3

Irrigating area in 30 minutes if 8cm of standing water is desired = `45000/0.08`

=`45000/0.08` = 562500m2

∴ Irrigated area in 30minutes = 562500m2

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APPEARS IN

 RD Sharma Solution for 10 Mathematics (2018 to Current)
Chapter 14: Surface Areas and Volumes
Q: 40
Solution Water in a Canal 1.5m Wide and 6m Deep is Flowering with a Speed of 10km/ Hr. How Much Area Will It Irrigate in 30 Minutes If 8cm of Standing Water is Desired? Concept: Volume of a Combination of Solids.
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