#### Question

A vessel in the shape of cuboid ontains some water. If these identical spheres are immersed in the water, the level of water is increased by 2cm. if the area of base of cuboid is 160cm^{2} and its height 12cm, determine radius of any of spheres?

#### Solution

Given that area of cuboid = 160cm^{2}

Level of water increased in vessel = 2cm

Volume of a vessel = 160 x 2cm^{3} .......(1)

Volume of each sphere =`4/3pir^3cm^3`

Total volume of 3 spheres `=3xx4/3pir^3cm^3` ...........(2)

Equating (1) and (2) āµVolumes are equal V_{1 }= V_{2}

`160xx2=3xx4/3pir^3`

`r^3=(160xx2)/(3xx4/3pi)

`r^3=320/(4pi)`

r = 2.94cm

∴ Radius of sphere = 2.94cm

Is there an error in this question or solution?

Solution A Vessel in the Shape of Cuboid Ontains Some Water. If These Identical Spheres Are Immersed in the Water, the Level of Water is Increased by 2cm. If the Area of Base of Cuboid is 160cm2 Concept: Volume of a Combination of Solids.