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# A Cylindrical Tube of Radius 12cm Contains Water to a Depth of 20cm. a Spherical Ball of Radius 9cm is Dropped into the Tube and Thus Level of Water is Raised by Hcm. What is the Value of H_____? - CBSE Class 10 - Mathematics

ConceptVolume of a Combination of Solids

#### Question

A cylindrical tube of radius 12cm contains water to a depth of 20cm. A spherical ball of radius 9cm is dropped into the tube and thus level of water is raised by hcm. What is the value of h.

#### Solution

Given that radius of cylindrical tube (r1) = 12cm

Let height of cylindrical tube (h)

Volume of a cylinder = pir_1^2h

v1 = π(12)2 x h                 ............(1)

Given spherical ball radius (r2) = 9cm

Volume of sphere = 4/3pir_2^3

v_2=4/3xxpixx9^2      ..............(2)

Equating (1) and (2)

v1 = v2

pi(12)^2xxh=4/3xxpixx9^3

h=(4/3xxpixx9^3)/(pi(12)^2)

h = 6.75cm

Level of water raised in tube (h) = 6.75cm

Is there an error in this question or solution?

#### APPEARS IN

RD Sharma Solution for 10 Mathematics (2018 to Current)
Chapter 14: Surface Areas and Volumes
Ex. 14.10 | Q: 43 | Page no. 30
Solution A Cylindrical Tube of Radius 12cm Contains Water to a Depth of 20cm. a Spherical Ball of Radius 9cm is Dropped into the Tube and Thus Level of Water is Raised by Hcm. What is the Value of H_____? Concept: Volume of a Combination of Solids.
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