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Sum
Verify that the following is an AP, and then write its next three terms.
`5, 14/3, 13/3, 4,...`
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Solution
Here,
a1 = 5
a2 = `14/3`
a3 = `13/3`
a4 = 4
a2 – a1 = `14/3 - 5 = -1/3`
a3 – a2 = `13/3 - 14/3 = -1/3`
a4 – a3 = `4 - 13/3 = -1/3`
Since, difference of successive terms are equal,
Hence `5, 14/3, 13/3, 4…` is an AP with common difference `-1/3`.
Therefore, the next three term will be,
`4 + (-1/3), 4 + 2(-1/3), 4 + 3(-1/3)`
`11/3 , 10/3, 3`
Concept: Arithmetic Progression
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