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Verify that the Given Functions (Explicit Or Implicit) is a Solution of the Corresponding Differential Equation X + Y = Tan–1y : Y2 Y′ + Y2 + 1 = 0 - Mathematics

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Question

verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation

x + y = tan–1y   :   y2 y′ + y2 + 1 = 0

Solution

x + y = tan–1y

Differentiating both sides of this equation with respect to x, we get:

Hence, the given function is the solution of the corresponding differential equation.

  Is there an error in this question or solution?
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APPEARS IN

 NCERT Solution for Mathematics Textbook for Class 12 (2018 (Latest))
Chapter 9: Differential Equations
Q: 9 | Page no. 385
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Verify that the Given Functions (Explicit Or Implicit) is a Solution of the Corresponding Differential Equation X + Y = Tan–1y : Y2 Y′ + Y2 + 1 = 0 Concept: General and Particular Solutions of a Differential Equation.
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